2(x^2+3)+y=x(2x+3)

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Solution for 2(x^2+3)+y=x(2x+3) equation:


Simplifying
2(x2 + 3) + y = x(2x + 3)

Reorder the terms:
2(3 + x2) + y = x(2x + 3)
(3 * 2 + x2 * 2) + y = x(2x + 3)
(6 + 2x2) + y = x(2x + 3)

Reorder the terms:
6 + 2x2 + y = x(3 + 2x)
6 + 2x2 + y = (3 * x + 2x * x)
6 + 2x2 + y = (3x + 2x2)

Add '-2x2' to each side of the equation.
6 + 2x2 + -2x2 + y = 3x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6 + 0 + y = 3x + 2x2 + -2x2
6 + y = 3x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6 + y = 3x + 0
6 + y = 3x

Solving
6 + y = 3x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + y = -6 + 3x

Combine like terms: 6 + -6 = 0
0 + y = -6 + 3x
y = -6 + 3x

Simplifying
y = -6 + 3x

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